用C将字符串打散成3个字符一组，每组按固定字符替换，然后输出替换结果

显示全部楼层 · 2009-7-1 14:56:15

程序如下，已在win-tc和dev-c++下编译通过，结果正确。#include#include#includeint main(){
int i,j=0;
char s[256]={'\0'},b[256]={'\0'};
printf("Please input a string:\n");
gets(s);
for(i=0;i<strlen(s)-2;i+=3)
if(s=='1'&&s[i+1]=='1'&&s[i+2]=='1')
{
b[j]='w';
b[j+1]='o';
j+=2;
}
else if(s=='1'&&s[i+1]=='1'&&s[i+2]=='2')
{
b[j]='a';
b[j+1]='i';
j+=2;
}
else if(s=='1'&&s[i+1]=='1'&&s[i+2]=='3')
{
b[j]='n';
b[j+1]='i';
j+=2;
}
printf("The result is:\n");
printf("%s\n",b);
system("pause");
return 0;}

千问 · 2009-7-1 14:56:15

100分……动手写写吧~~