求翻译A possible explanation for the very efficient DNA photocleavage

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查看11 | 回复3 | 2010-6-8 09:42:49 | 显示全部楼层 |阅读模式
A possible explanation for the very efficient DNA photocleavage
of 3 is the additional involvement of the 3MLCT
excited state.With E00B2.1 eV and E1/2([Ru]2+/+])=0.46 V
vs. NHE, an excited state reduction potential, Ered*, of
B1.64 V vs. NHE can be estimated for 3, making it a strong
oxidizing agent. Using +1.29 V vs. NHE as the oxidation
potential of guanine in water at pH = 7,21 a favorable driving
force of 0.35 V for the generation of G+ from the 3MLCT
state of 3 is calculated. Guanine oxidation by the excited states
of Ru(II) complexes has been previously shown to result in
DNA cleavage and adduct formation.3a,22 Although DNA
photocleavage from guanine oxidation was reported for
[Ru(hat)3]2+ (hat = 1,4,5,8,9,12-hexaazatriphenylene), a
complex with similar excited state reduction potential as that
of 3, 80% DNA damage required 3 min irradiation at
436 nm.22b As shown in Fig. 4a, irradiation of 3 for only 30 s
results in nearly quantitative DNA cleavage.

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千问 | 2010-6-8 09:42:49 | 显示全部楼层
对于络合物3非常高效的DNA光断裂的可能解释是额外牵涉了3MLCT激发态。在E00~2.1eV和E1/2([Ru]2+/+)=-0.46V相对于NHE情况下,对3可以估计一个~1.64V相对于NHE的激发态还原电位,使它成为一种强氧化剂。采用+1.29V相对于NHE作为鸟嘌呤在pH=7的水中的氧化电位,计算得到从3的3MLCT态发生G+-0.35V的良好推动力。由Ru(II)络合物的激发态产生鸟嘌呤氧化以前已证明会导致DNA断裂和加成化合物的形成3a,22。虽然由于鸟嘌呤氧化引起的DNA光断裂对[Ru(hat)3]2+(hat=1,4,5,8,9,12-高荧光量子效率三亚吡嗪),一种与3具有类似激发态还原电位的络合物已做了报道,但80%的DNA损坏要求
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千问 | 2010-6-8 09:42:49 | 显示全部楼层
一种可能的解释非常有效的3光断裂DNA的是额外的V主场迎战2 +/+])=茹参与的3MLCT兴奋state.With E00B2.1电子伏特和E1 / 2([] 0.46 NHE的,一个激发态还原电位,Ered *,对B1.64 v与NHE的可估计为3,使其成为一个强氧化剂。采用1.29 V 0.35 v与NHE的鸟嘌呤氧化电位水的pH值= 7,21在一个有
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千问 | 2010-6-8 09:42:49 | 显示全部楼层
一个可能的解释很能干的DNAphotocleavage三是增加对3mlct兴奋state。withe00b2。1电动车和e1/二((俄罗斯Z2/Z)时候探视病人0。46V与nhe,兴奋的状态,降低ered*,b1。64V与nhe估计为3,一氧化agen
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