写一个简单的计算机器，做二元运算-*/和%运算，运算完成后可以让用户选择输入y或者Y，以重复执行前面的运算，输入N或者n结束程序我所编写的代码如下：#includestdio.hintmain(void){doublenumber1=0.0;doublenumber2=0.0;charoperation=0;charanswer=0;there:printf(\"\\nPleaseinputthejisuanshuju:\\n\");scanf(\"%lf%c%lf\",switch(operation){case\'\':printf(\"=%lf\\n\",number1number2);break;case\'-\':printf(\"=%lf\\n\",number1-number2);break;case\'*\':printf(\"=%lf\\n\",number1*number2);break;case\'/\':if(number2==0)printf(\"\\n\\nbeichushubunengwei0!\\n\");elseprintf(\"=%lf\\n\",number1/number2);break;case\'%\':if((long)number2==0)printf(\"\\n\\nbeichushubunengwei0!\\n\");elseprintf(\"=%ld\\n\",(long)number1%(long)number2);break;default:printf(\"\\n\\ninvalidshuju!\\n\");printf(\"\\n\\nPleaseinputtheshujuonceagain:\\n\");}printf(\"\\nwewillcontinuetotheprograme,pressYyorNn:\");scanf(\"%c\",if(answer==\'Y\'||answer==\'y\')gotothere;elseif(answer==\'N\'||answer==\'n\')printf(\"wewillendtheprograme\");return0;}这行代码编译可以通过并生成EXE文件，但是运行的时候并没有按照我原先的意图运行起来，请问代码到底在哪里出了问题
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