IP怎么求？急~

显示全部楼层 · 2010-12-27 11:22:49

A large number of consecutive IP address are available starting at 198.16.0.0. Suppose that four organizations,A,B,C and D,request 4000,2000,4000,and 8000 addresses,respectively,and in that order. For each of these,give the first IP address assigned,the last IP address assigned,and the mask in the w.x.y.z/s notation.
最好能有具体过程啊~~

千问 · 2010-12-27 11:22:49

给定的这个地址198.16.0.0能分配255*255-4个地址。根据你的四个组的要求4000 2000 4000 8000 可以很好分配的。主要是掩码的换算。比如说第一组要4000个地址。你可以198.16.1.0~198.16.16.0这个地址就够用了。16*256=4096个地址。再减去每组不能用的IP。16*2=32。4064个地址。然后再算一下掩码。就可以了。基本原理就是这样的。具体算法。网上一大堆。就不罗嗦了