1. 令y=0,得f[(x+0)/2]=f(x)sina+(1-sina)f(0)f(x/2)=f(x)sina+1-sina。。。(1)令x=1, f(1/2)=1令x=1/2, f(1/4)=12. 设f(t)=0 令x=t,由(1)得 f(t/2)=1-sina令x=t/2, 由(1)得 f(t/4)=(1-sina)sina+1-sina=1-(sina)^2令x=t,y=t/2,由原关系式得 f((t+t/2)/2)=(1-sina)^2=f(3t/4)令x=3t/4,y=t/4,由原关系式得 f((3t/4+t/4)/2)=(1-sina)^2*sina+(1-sina)(1-(sina) |