(1)若a>0,且tan角POB=1/9,设B(m,1/m),1/9=1/m^2,a>0,m>0,m=3y=1/3A(1/3,1/3)AB=3-1/3=8/3线段AB的长为8/3(2)在过A,B两点且顶点在直线y=x上的抛物线中,已知线段AB=8/3,,试求出满足条件的抛物线的解析式y=ax^2+bx+cAB=8/3设B(m,1/m),A(1/m,1/m)(m-1/m|=8/3,3|m^2-1|=8|m|,且在它的对称轴左边时,y随着x的增大而增大,抛物线开口向下,a1(3m+1)(m-3)=0,m=3A(1/3,1/3),B(3,1/3)顶点C坐标C(10/
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