内的2,3,5,7的倍数(除2之外)去掉,就是所有质数啦 #include#includeusing namespace std;int main(){ int i,j,sum=0,k=0; bool flag=true; for(i=2;i<=100;i++) { if(i==2 || (i%2!=0 && i%3!=0 && i%5!=0 && i%7 != 0) ){
if(k%5==0)
cout<<endl; //每5个换一行
k++;
cout<int main(){int i,j,k,n;n=1for(i=1;i<=5;i++)for(j=1;j<=5;j++)for(k=1;k<=2;k++)if(n<=30)printf()//略}
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