为避免同一本书被同一个人借走很多次的情况:select t1.bookId,t1.bookname,t1.author,t2.count from books as t1,(select bookId,count(1) as count from (select bookId,memberId from member group by bookId,memberId) as t group by bookId) as t2 where t1.bookId=t2.bookId当然如果不在乎这个,一楼仁兄的即可
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