ABAP 高手请进

显示全部楼层 · 2011-3-16 19:33:27

现有一内表itab :
A B
C
A B
C
A B
C
A B
C
1 1
1
1 1
1
1 1
1
我想分别统计 A 输出了多少行 1输出了多少行应该如何实现

千问 · 2011-3-16 19:33:27

TYPES:BEGIN OF l_type_itab,
field1 TYPE c LENGTH 1,
field2 TYPE c LENGTH 1,
field3 TYPE c LENGTH 1,END OF l_type_itab.DATA:
l_it_data TYPE STANDARD TABLE OF l_type_itab,
l_wa_data TYPE l_type_itab,
l_a_num TYPE i,
l_1_num TYPE i.l_wa_data-field1 = 'A'.l_wa_data-field2

千问 · 2011-3-16 19:33:27

data:l_count type i.sort itab by fielda. loop at itab into wa.at new fielda.clear l_count.endat.l_count = l_count +1.at end of fielda.write:/ 'count:=',l_count.

千问 · 2011-3-16 19:33:27

tab occurs 0 ,
type_count type i ,
mara_count type i ,
end of itab .**定义sy-tabix 。DATA:L_INDEX LIKE SY-TABIX.** 新增物料组计算资料到itab select distinct co

千问 · 2011-3-16 19:33:27

假设你的内表的三个字段的名字为：COL1, COL2,COL3.DATA: LV_COUNTER TYPE I.SORT ITAB COL1.LOOP AT ITAB INTO LW_ITAB.LV_COUNTER = LV_COUNTER + 1.AT END OF COL1. WRITE:/ LW_ITAM-COL1,':',