vb中如何在picture中输出 1 12 123 1234 132345

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查看11 | 回复5 | 2011-4-13 12:23:29 | 显示全部楼层 |阅读模式
是要换行的第一行是1,第二行是12
以此类推,要用到双循环..Picture1.Cls
Dim k As Integer, i As Integer, n As Integer, c As String, s As String
k = 5
For i = 1 To k
For n = 1 To i
Picture
Next n
Next i我做到这步发现输出的不一样..郁闷呐..求大侠们帮帮忙

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千问 | 2011-4-13 12:23:29 | 显示全部楼层
Private Sub Command1_Click()For i = 1 To 5For j = 1 To iPicture1.Print j;Next jPicture1.PrintNext iEnd SubPrivate Sub Command2_Click()For i = 1 To 5For j = i To 1 Step -1Picture1.Print j;Next jPicture1.PrintNext iEnd Sub
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千问 | 2011-4-13 12:23:29 | 显示全部楼层
Option ExplicitPrivate Sub Command1_Click()Dim i%, k%For i = 1 To 5
For k = 1 To i
Picture1.Print CStr(k);
Next kPicture1.PrintNext iEnd SubPrivate
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千问 | 2011-4-13 12:23:29 | 显示全部楼层
Private sub command1_click()Print "1"Print "1" & "2"Print "1" & "2" & "3"Print "1" & "2" & "3" & "4"Print "1" & "2" & "3" & "4" & "5"End sub Private sub command2_clic
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千问 | 2011-4-13 12:23:29 | 显示全部楼层
dim a=1For a=1 TO 5picture aNEXT a
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千问 | 2011-4-13 12:23:29 | 显示全部楼层
Picture1.Print " 1 12 123 1234 132345 "
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