用十字相乘法分解因式：（1）x^2+y^2-2xy-10x+10y+16=? （2）2x^2+3xy-2y^2-x+8y-6=? 要有过程，谢谢啊！

显示全部楼层 · 2011-4-22 09:09:55

希望能够帮到你

千问 · 2011-4-22 09:09:55

x^2+y^2-2xy-10x+10y+16=（x-y)^2-10(x-y)+16
=(x-y-8)(x-y-2)2x^2+3xy-2y^2-x+8y-6=(2x-y)(x+2y)-(x-8y)-6
=(x+2

千问 · 2011-4-22 09:09:55

1·（x-y）^2-10(x-y)+16=(x-y-8)(x-y-2)2`(x+2y)(2x-y)-(x-8y)-6=(x+2y-2)(2x-y+3)

千问 · 2011-4-22 09:09:55

1·（x-y）^2-10(x-y)+16=(x-y-8)(x-y-2)2`(x+2y)(2x-y)-(x-8y)-6=(x+2y-2)(2x-y+3)