1.编写一程序，求1!/2!+2!/3!+…+(N-1)!/N!,要求采用递归函数实现。（难度：A+）int Factorial( int n ){ if(n=1)
return 1; else
return n*Factorial(n-1);}int Sum( int n ){int sum=0;
int i=0;
for(i=1;i #include#includefloat factorial(float n);int main() {int i;float t=0,total=0,n;printf("please input the n:");scanf("%f",
