(a+1)(a2+1)(a4+1)(a8+1)(a16+1)=?

显示全部楼层 · 2008-10-16 23:36:04

∵(a-1)[(a+1)(a2+1)(a4+1)(a8+1)(a16+1)]=(a^2-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a^4-1))(a^4+1)(a^8+1)(a^16+1)=...=a^32-1∴(a+1)(a2+1)(a4+1)(a8+1)(a16+1)=(a^32-1)/(a-1)...

千问 · 2008-10-16 23:36:04

(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)=(a-1)[(a+1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[a^2-1)(a^2+1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^4-1)(a^4+1)(a^8+1)(a^16+1)]/(a-1)=[(a^8-1...