#include
#include
void main()
{
float a,b,c,x1,x2,disc;
scanf("%8.4f,%8.4f,%8.4f",&a,&b,&c);
if(fabs(a)=1e-6)
{x1=(-b+sqrt(disc))/(2*a);
x2=(-b-sqrt(disc))/(2*a);
printf("%8.4f,%8.4f\n,x1,x2");
}
else
{x1=-b/(2*a)+(sqrt(-disc)/(2*a))*i;
x2=-b/(2*a)-(sqrt(-disc)/(2*a))*i;
printf("%8.4f,%8.4f\n",x1,x2);
}
}
}/*求a x2+bx+c=0的解*/
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