遍程计算S=1+2+3+…+50，并求成1~50之间的偶数之和。

显示全部楼层 · 2008-12-9 16:56:20

VF编程题……帮忙解答……谢谢！！！

千问 · 2008-12-9 16:56:20

/*VC++6.0编译通过*/#includeusing namespace std;int main(){ int sum=0; int evensum=0; for(int i=1;i<=50;i++) {sum+=i;if(i%2==0)evensum+=i; } cout<<"1-50数的和是"<<sum<<" "<<"1-50偶数的和是"<<evensum<<endl; system("pause"); return 0;}...

千问 · 2008-12-9 16:56:20

settalkoffi=1 n=0 s=0m=0DO WHILE i<=50s=s+im=m+ni=i+1n=n+2EDNDO?S ?msettalkonreturn...

千问 · 2008-12-9 16:56:20

for i=1 to 50s=s+ifor i=2 to 50 setup=2s=s+i小狐狸好久都没用过了~不知道对不对~...