0.1L pH=2盐酸和0.1L pH=11的NaOH溶液相混合，求混合后溶液的pH值

显示全部楼层 · 2008-11-19 22:00:22

0.1L pH=2盐酸的物质的量为0.1*0.01=0.001摩尔0.1L pH=11的NaOH溶液的物质的量=0.1*0.001=0.0001摩尔完全反应后，PH=lg0.00099...

千问 · 2008-11-19 22:00:22

0.1L pH=2盐酸c(H+)=10^(-2)0.1L pH=11的NaOH溶液pOH=3所以c(OH-)=10^(-3)所以~反应后c(H+)=999*10(-3)=9.99*10(-5)所以pH=5-lg9.99...

千问 · 2008-11-19 22:00:22

解：n(H+)=0.1*0.01-0.1*0.001=0.1*0.099 C(H+)=0.1*0.099/0.2 PH=-lgC(H+)=2-lg4.95...