这是一个求当天是一年中第几天的程序 但是编写了下面的第一个代码觉得效率不高又写了类似的一个第二个为什么第儿歌不可以运行 望高手指教
#include
void main()
{
int f(int year,int month,int day);
int year,month,day,c;
scanf("%d %d %d",&year,&month,&day);
c=f(year,month,day)+day;
printf("number is %d day\n",c);
}
int f(int year,int month,int day)
{
int i,number1;
number1=0;
if((year%4==0 && year%100!=0) || (year%400==0))
{
int a[13]={0,31,29,31,30,31,30,31,31,30,31,30,31};
for (i=0;i<month;i++)
{
number1=a+number1;
}
}
else
{
int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
for (i=0;i<month;i++)
{
number1=a+number1;
}
}
return(number1);
}
void main()
{
int f(int year,int month,int day);
int year,month,day,Number;
scanf("%d %d %d",&year,&month,&day);
Number=f(year,month,day);
printf("number is %d day\n",Number+day);
}
int f(int year,int month,int day)
{
int number1,i;
number1=0;
if((year%4==0 && year%100!=0)||(year%400==0))
int a[13]={0,31,29,31,30,31,30,31,31,30,31,30,31};
else
int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
for(i=0;i<month;i++)
{
number1=number1+a;
}
return(number1);
}
儿歌--二个
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