数学专题，求高手过程解答

显示全部楼层 · 2013-10-28 07:55:49

(1) tana=2/1=2 (2) 2sin2x+sinxcosx =(2sin2x+sinxcosx)/1 =(2sin2x+sinxcosx)/(sin2x+cos2x) 分子分母同时除以cos2x =(2sin2x/cos2x+sinxco/sx)/(sin2x/cos2x+1) =(2tan2x+tanx)/(tan2x+1) =(2*22+2)/(22+1) =10/5 =2 
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千问 · 2013-10-28 07:55:49

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