#include
#define SIZE 50
int main()
{
int command; /*用户输入的命令*/
int moveNumber; /*移动的步数*/
int orientation;/*存储方向*/
int x;
int y;
int floor[SIZE][SIZE] = { 0 };
int i = 0;
int j = 0;
int pen = 1; /*默认笔向上*/
/*游戏说明*/
printf( "命令
含义\n" );
printf( "1
笔在上\n" );
printf( "2
笔在下\n" );
printf( "3
向右转\n" );
printf( "4
向左转\n" );
printf( "5
向前移动10个空格(或者10以外的其它数字)\n" );
printf( "6
输出20乘20数组\n" );
printf( "9
数据结束(标志)\n" );
printf( "\n\n\n请输入命令: " );
scanf( "%d", &command );
while( command != 9 )
{
switch( command )
{
case 1:
pen = 1;
break;
case 2:
pen = 2;
break;
case 3:
orientation = 0; /*0为向右转*/
break;
case 4:
orientation = 1; /*1为向左转*/
break;
case 5:
printf( "输入要移动的步数: " );
scanf( "%d", &moveNumber );
if( orientation == 0 )
{
if( i == 0 && j == 0 )
{
j = j + moveNumber;
for( x = 0; x0 )
{
i += moveNumber;
for( x = 0; x0 && j > 0 )
{
j = j - moveNumber;
for( x = j; x >= j - moveNumber ; x-- )
{
if( pen == 2 )
{
floor[x] = 1;
}
}
break;
}
if( i > 0 && j == 0 )
{
i = i - moveNumber;
for( x = i; x >= i - moveNumber; x--)
{
if( pen == 2 )
{
floor[x][j] = 1;
}
}
break;
}
}
case 6:
for( x = 0; x <= 19; x++)
{
for( y = 0; y <= 19; y++)
{
if( floor[x][y] == 0 )
{
printf( "" );
}
if( floor[x][y] == 1 )
{
printf( "# " );
}
if( y == 19 )
{
printf( "\n" );
}
}
}
break;
}
printf( "请输入命令: " );
scanf( "%d", &command );
}
return 0;
}
这个程序只完成了部分功能
我输入,2,3,5,12,可以输出12个#
再输3,5,12,又输出12个#
再输3,5,12就不能输出12个#了,只有一个
请高手看下哪错了
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