加拿大物理题哪位大侠能帮着解答一下啊.谢谢.急!!

显示全部楼层 · 2009-3-8 11:54:21

A pole-vaulter approaches the takeoff point at a speed of 6.70 m/s. Assuming that only this speed determines the height to which he can rise, find the maximum height at which the vaulter can clear the bar.

千问 · 2009-3-8 11:54:21

在竖直方向上，已知：v=6.7m/s,a=g=9.8/s^s求：h=?解：v=at>t=v/a;
=6.7m/s/9.8m/s^s
=6.7/9.8s;h=vt-1/2gt^t =2.28m则该运动员最高可跳2.28米；不一定对啊，高中的知识忘得差不多了。...