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查看11 | 回复3 | 2009-4-3 14:14:20 | 显示全部楼层 |阅读模式
The first thing you have to realize about proving Taylor's theorem is that there are infinitely many versions of Taylor's theorem: one for each possible expression of the remainder term. In other words, what a Taylor's theorem really is is a proof that a certain expression involving n gives the nth remainder term, i.e. the diffierence between the nth Taylor polynomial and the function it approximates.
With that in mind we can motivate the Lagrange remainder form by (A) setting out to simply find some expression for the remainder, (B) generalizing our first attempt and discovering an infinite class of expressions for the remainder, and finally (C)
settling on the Lagrange form since it is somehow the most beautiful and compelling form in this class (or, on more pragmatic grounds, since it promises to be the most useful).

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千问 | 2009-4-3 14:14:20 | 显示全部楼层
The first thing you have to realize about proving Taylor's theorem is that there are infinitely many versions of Taylor's theorem: one for each possible expression of the remainder term. In other words, what a Taylor's theorem really is a proof that a certain expression involving n gives the nth remainder term, i.e. the differen...
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千问 | 2009-4-3 14:14:20 | 显示全部楼层
首先,你必须认识到约证明泰勒定理的是,有无穷多个版本的泰勒定理:每个可能表达的剩余任期。换句话说,什么是泰勒定理真的是一个证据,证明某个表达式涉及?使第n个剩余任期,即diffierence之间的n次方泰勒多项式和它的功能接近。 考虑到这一点我们可以激发拉格朗日其余形式包括: (一)制定了简单地找到了一些表达的剩余时间, (乙)推广我们...
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千问 | 2009-4-3 14:14:20 | 显示全部楼层
您必须体会关于证明泰勒的定理的第一件事是无限地有泰勒的定理的许多版本: 一余项的每个可能的表示的。 真正换句话说,泰勒的定理is is介入n的某一表示给第n余项的证明,即在多项第n的泰勒和作用之间的diffierence它接近。 我们可以通过(a)发现剩下的人的某一表示的开始鉴于此刺激拉格朗日剩下的人形式, (b)推断我们的第一个尝试和发现表示无限类剩下...
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