解方程(2x-1)^2-10(2x-1)+25=0 （1+√2）x^2-(1-√2)x=0 用分解因式做啊过程详细啊

显示全部楼层 · 2011-8-21 19:35:49

(2x-1)^2-10(2x-1)+25=0 (2x-1-5)2=0(2x-6)2=0∴x=3（1+√2）x^2-(1-√2)x=0 x[(1+√2)x-(1-√2)]=0x=0
(1+√2)x-(1-√2)=0x=0
x=(1-√2)/(1+√2)=(1-√2)2/(1-2)=-(1-√2)2=-1+2√2-2=2√2-3∴x=0或x=2√2-3...

千问 · 2011-8-21 19:35:49

(2x-1)^2-10(2x-1)+25=0 (2x-1-5)^2=0(2x-6)^2=02x-6=02x=6x=3（1+√2）x^2-(1-√2)x=0 x[(1+√2)x-(1-√2)]=0x=0或(1+√2)x=(1-√2)x=0或 x=(1-√2)÷(1+√2)x1=0x2=2√2-3...

解方程(2x-1)^2-10(2x-1)+25=0 （1+√2）x^2-(1-√2)x=0 用分解因式做啊 过程详细啊

解方程(2x-1)^2-10(2x-1)+25=0 （1+√2）x^2-(1-√2)x=0 用分解因式做啊过程详细啊