令,点A(1,4)关于直线X-2Y=0的对称点为A1(X1,Y1),关于直线X+Y-1=0的对称点为A2(X2,Y2),则直线AA1的斜率为K1=-2.直线AA2的斜率为K2=1.则,直线AA1的方程为:Y-4=-2(X-1),即,2X+Y-6=0,直线AA2的方程为:Y-4=(X-1),即,X-Y+3=0,2X+Y-6=0,X-2Y=0,解方程得,X=12/5,Y=6/5.即,AA1中点坐标为(12/5,6/5).12/5=(X1+1)/2,6/5=(Y1+4)/2.X1=19/5,Y1=-8/5.X-Y+3=0,x+y-1=0.解得,X=-1,Y=2.即,AA2中点坐标为(-1,2),...
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