先化简，再求值：(x^2+5x+6)/(x+3)÷(x^2-4)/(x-3)-1,其中x=根号3

显示全部楼层 · 2011-2-2 17:38:10

先化简，再求值：(x2+5x+6)/(x+3)÷(x2-4)/(x-3)-1,其中x=√3解：原式＝[(x+2)(x+3)/(x+3)]×[(x-3)/(x-2)(x+2)]-1=(x-3)/(x-2)-1=[(x-3)-(x-2)]/(x-2)=-1/(x-2)=-/(√3-2)=(√3)+2...

千问 · 2011-2-2 17:38:10

（x+2)(x+3)
(x+2)(x-2)
（x+2)(x+3)
(x-3)
(x-3)-----------------÷--------------- -1=
------------------ X ---------------=--------...

千问 · 2011-2-2 17:38:10

题不太清楚原式=(x+2)(x+3)/(x+3)÷(x+2)(x-2)/(x-4)
=(x+2)÷(x+2)(x-2)/(x-4)
=(x-4)/(x+2) 将x=根号3代入，得(根号3-4)/ (根号3+2）...

千问 · 2011-2-2 17:38:10

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