(1/2)已知有理数a b c 满足la-1l+(b+3)的平方+(3c-1)2n次方=O(n为正整数)求(abc)125次方/(a9次方b3次

显示全部楼层 · 2011-10-8 22:17:24

la-1l+(b+3)的平方+(3c-1)2n次方=Oa-1=0b+3=03c-1=0a=1b=-3c=1/3(abc)^125=(-3*1*1/3)^125=(-1)^125=-1a^9b^3c^2=1^9*(-3)^3*(1/3)^2=1*(-27)*1/9=-3...

千问 · 2011-10-8 22:17:24

解：由题意a-1=0且b+3=0且3c-1=0，故a=1，b=-3,c=1/3(abc)125次方/(a9次方b3次=(-1)125次方/(1的9次方-3的3次方=-1/-27=1/27...

千问 · 2011-10-8 22:17:24

la-1l+(b+3)^2+(3c-1)2n次方=0a-1=0
a=1b+3=0
b=-33c-1=0
c=1/3(abc)125次方/(a9次方b3次方）=【1×（-3）×1/3】^125/【1^9×（-3）^3】=【-1】^125/【1×（-27）】=-1/（-27）=1/27...