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X=3+1,y=9+(1/3),试求y与x的函数关系式解：用a^b表示a的b次方X=3^m+1,y=9^(-m)+(1/3)^m所以 3^m=X-1y=9^(-m)+(1/3)^m=[3^2]^(-m)+(1^m)/(3^m)=3^(-2m)+1/(3^m)=(3^m)^(-2)+1/(3^m)=(X-1)^(-2)+1/(X-1)=1/[(X-1)^2]+(X-1)/[(X-1)^2]=X/[(X-1)^2]2.已知：a+x方=2005，b+x方=2006，c+x方=2007，切abc=24，求a/bc+b/ac+c/ab-1/a-1/b-1/c的值...
