有一位同学说:“整式7x^3—6x^2y+3x^2y+3x^3+6x^2y—3x^2y-10x^3的值与x,y的取值无关。”

显示全部楼层 · 2011-10-30 16:27:04

有道理，将整式合并同类项，化简后=0...

千问 · 2011-10-30 16:27:04

-(3x^2y+10x^3)+3x^3+6x^3y+3x^2y-(6x^3y-7x^3)= -3x^2y-10x^3+3x^3+6x^3y+3x^2y-6x^3y+7x^3= -3x^2y+3x^2y -10x^3+3x^3+7x^3 + 6x^3y-6x^3y= 0 + 0 + 0= 0...

千问 · 2011-10-30 16:27:04

整式7x^3—6x^2y+3x^2y+3x^3+6x^2y—3x^2y-10x^3的值与x,y的取值无关这必然对啊···7x^3—6x^2y+3x^2y+3x^3+6x^2y—3x^2y-10x^3=0祝学习顺利...

千问 · 2011-10-30 16:27:04

整式7x^3—6x^2y+3x^2y+3x^3+6x^2y—3x^2y-10x^3的值与x,y的取值无关这必然对啊···7x^3—6x^2y+3x^2y+3x^3+6x^2y—3x^2y-10x^3=0你可以化简一下试一试啊...

千问 · 2011-10-30 16:27:04

就是等于0我想他的式子是这样的：7x^3-6x^2*y+3x^2*y+3x^3+6x^2*y-3x^2*y-10x^3=0...