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设A（x1,y1）、B(x2,y2),N(x,y),则x=(x1+x2)/2,y=(y1+y2)/2...............................（1）x1^2/4+y1^2=1x2^2/4+y2^2=1相减得到：（x1^2-x2^2)/4+(y1^2-y2^2)=0,即（x1-x2)(x1+x2)/4+（y1-y2)(y1+y2)=0两边同除（x1-x2)，将（1）式代入，化简：2x/4+2y*（y1-y2)/(x1-x2)=0.............................(2)由于AB与F1N共线：（y1-y2)/(x1-x2)=(y-0)/(x+根号3)代入(2)式，2x/4+2y*y/(x+根... |
