∫ln²x/x²dx

显示全部楼层 · 2012-12-5 09:15:48

∫ln2x/x2dx=-∫ln2xd(1/x)=-(ln2x)/x+∫1/x*dln2x=-(ln2x)/x+∫1/x*2*lnx *1/x*dx=-(ln2x)/x+∫1/x2*lnx*dx=-(ln2x)/x-∫lnx*d(1/x)=-(ln2x)/x-(lnx)/x+∫1/x*d(lnx)=-(ln2x)/x-(lnx)/x+∫1/x*1/x *dx=-(ln2x)/x-(lnx)/x+∫1/x2*dx=-(ln2x)/x-(lnx)/x-∫d(1/x)=-(ln&#1...

千问 · 2012-12-5 09:15:48

jln2x/x2dx=-∫ln2xd(1/x)=-(ln2x)/x+∫1/x*dln2x=-(ln2x)/x+∫1/x*2*lnx *1/x*dx=-(ln2x)/x+∫1/x2*lnx*dx=-(ln2x)/x-∫lnx*d(1/x)=-(ln...