初一的数学题已知x不等于2和x不等于5的所有x的值等

显示全部楼层 · 2012-12-15 16:00:35

(4x+1)/(x2-7x+10)=A/(x-2)-B/(x-5)(4x+1)/[(x-2)(x-5)]=[A(x-5)-B(x-2)]/[(x-2)(x-5)]4x+1=A(x-5)-B(x-2)4x+1=(A-B)x-5A+2BA-B=4
-5A+2B=1解A B方程组得A=-3B=-7...

千问 · 2012-12-15 16:00:35

(4x+1)/(x^2-7x+10)=A/(x-2)+B/(x-5)=[A(x-5)+B(x-2)]/(x-2)(x-5)(4x+1)/(x-2)(x-5)=[(A+B)x-(5A+2B)]/(x-2)(x-5)所以有:A+B=45A+2B=-12A+2B=8A=-3B=7...

千问 · 2012-12-15 16:00:35

整理得：x^2-(86/10)x+(10+5A+2B)/10=0恒成立，则b^2-4ac>=0，则有A<=34.98-0.4B的关系...

千问 · 2012-12-15 16:00:35

等式表述不清，有歧义...

千问 · 2012-12-15 16:00:35

x=-3，A=-3，B=-11...