(x+y)的n-1次幂*(x-y)的n+1次幂÷[三分之一(x+y)的n-3次幂（x-y)的n-1次幂]

显示全部楼层 · 2012-4-11 23:00:19

(x+y)的n-1次幂*(x-y)的n+1次幂÷[三分之一(x+y)的n-3次幂（x-y)的n-1次幂]=3(x+y)的n-1次幂*(x-y)的n+1次幂*(x+y)的3-n次幂（x-y)的1-n次幂=3(x+y)的(n-1+3-n)次幂*(x-y)的(n+1+1-n)次幂=3*(x+y)2(x-y)2=3(x2-y2)2...

千问 · 2012-4-11 23:00:19

(x+y)的n-1次幂*(x-y)的n+1次幂÷[三分之一(x+y)的n-3次幂（x-y)的n-1次幂]=3（x+y) ^ (n-1)*(x-y)^ ( n+1) / (x+y)^ ( n-3)*(x-y) ^ (n-1)=3(x+y) ^ [(n-1)-(n-3)]
* (x-y) ^ [(n+1)-(n-1)]...