(2)双曲线方程y^2-x^2=2,对x求导，y'=x/y,设直线m方程为：y=k(x-√2)设C(x0,y0)在双曲线上，C点切线斜率k1=x0/y0=k,C到直线m的距离为d=|kx0-y0-k*√2|/√(k^2+1)=√2,|kx0-y0-k*√2|=√2√(k^2+1) ,|x0^2/y0-y0-x0/y0*√2|=√2√((x0/y0)^2+1), |(x0^2-y0^2-√2*x0)/y0 |=√2√((x0/y0)^2+1),| (-2-√2*x0)/y0 |=√2√((x0/y0)^2+1),两边平方，((-2-√2*x0)/y0 )^2=2*((x0/y0)^2+1),(2+√2*x0)^2=2*(x...
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