f(x)=2^sin(2x-π/4)是否为周期函数?

显示全部楼层 · 2011-12-13 23:36:31

是。因为f(x)=2^sin(2x-π/4),所以f(x+π)=2^sin[2(x+π)-π/4]=f(x)=2^sin(2x-π/4),所以f（x+π）=f（x），f（x）是周期为π的周期函数...

千问 · 2011-12-13 23:36:31

sin(2x-π/4)的最小正周期为2*π/2=πf(x+π)=2^sin[2(x+π）-π/4]=2^sin[2x+2π-π/4]=2^sin(2x-π/4)=f(x)f(x)=2^sin(2x-π/4)是周期函数,最小正周期为π...

千问 · 2011-12-13 23:36:31

f(x+π)=2^sin(2x-π/4+2π)=2^sin(2x-π/4)=f(x)f(x-π)=2^sin(2x-π/4-2π)=2^sin(2x-π/4)=f(x)x属于实数域，f(x)周期函数...