表：a
id name
11 aaaa
11 bbbb
11 cccc
22 dddd
22 eeee
22 ffff
如何将表中的相同id号的第一条记录取出来？即：
id name
11 aaaa
22 dddd
select id1=identity(int,1,1),* into #t from a
go
select id,name from #t where id1 in(select min(id1) from #t group by id)
select * from a b
where name=(select top 1 name from a where id=b.id)
select id1=identity(int,1,1),* into #t from a
go
select id,name from #t where id1 in(select min(id1) from #t group by id)
这个我不大明白,我的QQ是120783975
有什么SQL的QQ群吗?
