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一道高数求曲线包围的面积的题求：y=-x^2+4x-3与函数在点(0,-3)和(3,0)处的切线所围成图形的面积clear all;clc;syms xy=-x^2+4*x-3;dydx=diff(y,1);k1=subs(dydx,{x},{0});%过点(0,-3)的切线y=4*x-3;k2=subs(dydx,{x},{3}); %过点(3,0)的切线y=-2*x+6;[x0,y0]=solve('4*x-3=y','-2*x+6=y','x','y');x0=eval(x0); %两切线的交点f1=@(x)x.^2;f2=@(x)x.^2-6*x+9;aera=quadl(f1,0... |
