令∫[0,x] f(x)dx=F(x)很明显F(0)=∫[0,0] f(x)dx=0由∫[0,1] f(x)dx=F(1)-F(0)=A=F(1)∫[0,1] ∫[x,1] f(x)f(t)dtdx=∫[0,1] f(x)∫[x,1] f(t)dtdx=∫[0,1] f(x)[F(1)-F(x)]dx=∫[0,1] [F(1)-F(x)]dF(x)=[F(1)F(x)-F^2(x)/2] [0,1]=F(1)F(1)-F^2(1)/2-F(1)F(0)+F^2(0)/2=F^2(1)/2=A^2/2...
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