二次函数

[复制链接]
查看11 | 回复1 | 2013-1-10 09:40:56 | 显示全部楼层 |阅读模式
y = -x2 + bx = x(b - x)与X轴有2个交点: O(0, 0), A(b, 0)对称轴: x = (0 + b)/2 = b/2x = b/2, y = -b2/4 + b*b/2 = b2/4顶点B(b/2, b2/4)OB的斜率m = (b2/4)/(b/2) = b/2AB的斜率n = (b2/4 - 0)/(b/2 - b) = -b/2mn = -1 = -b2/4b = ±2...
回复

使用道具 举报

您需要登录后才可以回帖 登录 | 立即注册

本版积分规则

主题

0

回帖

4882万

积分

论坛元老

Rank: 8Rank: 8

积分
48824836
热门排行