(1)由已知条件可知：U1/(R1+0.5R3)=I2，I2*R1=U1',I2*I2*R1=2W,U1:U1'=5:2,得出U1'=2/5U1，0.5R3=3/5U1(因为串联正比分压，U1为电路的端电压）最后由公式I2*I2*R1=2W,U1'=2/5U1,0.5R3=3/5U1，I2*R1=U1'联合求出R3=(6/25)*(U1*U1),在由U2*R3=P3=3/2W求出U2*U2=(9/25)*(U1*U1)和U1/U1'=5/2得出U1':U2=2:3在得出U2=3/5U1(2)由已知条件可知(R2+R3)*I3=U1，U2=R3*I3=3/5U1，I3*I3*R3=1.5W,I3*I3*R2=P2最后求出P2=1W(3) 由于S1...
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