解答如下,望采纳!(1)根据周期公式T=2π/w,有w=2π/π=2;最低点为M(π/3,-3),有-A-1=-3,sin(2*π/3+φ)=-1;于是可得,A=2;0<φ<π,所以2*π/3<2*π/3+φ<5*π/3,又sin(2*π/3+φ)=-1,所以2*π/3+φ=3π/2,可得φ=5π/6,所以f(x)=2sin(2x+5π/6)-1(2)令t=2x+5π/6,当x∈[-π/2,0]时,t∈[-π/6,5π/6],所以sint∈[-1/2,1],f(x)∈[-3,1];(3)就是令t=0,π/2,π,3π/2,2π时x的值,分别等于-5π/12,-π/6,π/12,π/3,7π/12.... |