边长为4的正方形ABCO放置于直角坐标系中,D E分别是OC,AB的中点,点F 为BC边上一动

显示全部楼层 · 2012-6-13 17:51:10

OF方程y＝4x/mCH方程y＝﹙-m/4﹚x+4.设P＝OF∩CH则P﹙16m/﹙16+m2﹚, 64/﹙16+m2﹚﹚H﹙a,b﹚ a＝2×[16m/﹙16+m2﹚]-0＝32m/﹙16+m2﹚, b＝2×[64/﹙16+m2﹚]-4＝﹙64-4m2﹚/﹙16+m2﹚, 即H﹙32m/﹙16+m2﹚, ﹙64-4m2﹚/﹙16+m2﹚﹚...

千问 · 2012-6-13 17:51:10

点H的坐标(4*COS{90-[Arctan(m/4)]*2}, 4*SIN{90-[Arctan(m/4)]*2})...