已知m=n^4-16的6次方根+16-n^4的6次方根/2-n+2n,求m^2-n的值

显示全部楼层 · 2013-2-25 20:35:48

m=n^4-16的6次方根+16-n^4的6次方根/2-n+2n,求m^2-n的值∵n?-16≥0
16-n?≥0 (n2+2)(n2-2)≥0
(4+n2)(4-n2)≥0∴ n2≥2
n2≤2∴n2=2n=±√2∴m=(n^4-16的6次方根+16-n^4的6次方根)/(2-n)+2n=0+2n=2nm2-n=4n2-n=8±√2...

千问 · 2013-2-25 20:35:48

m=n^4-16的6次方根+16-n^4的6次方根/2-n+2n=n^4-16^(1/6)+16-(n^4)^(1/6)/2-n+2n=n^4-(2^4)^(1/6)+16-(n^4)^(1/6)/2+n=n^4-2^(4/6)+16-n^(4/6)/2+n=n^4-2^(2/3)+16-n^(2/3)/2+n=n^4+n-n...