线性代数排列式求解~~

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1 | 2013-3-22 07:02:19 | 显示全部楼层 |阅读模式

x a ... aa x ... a.........a a ... x=[x+(n-1)a]1 a ... a1 x ... a.........1 a ... x=[x+(n-1)a]1 a ... a0 x-a ... 0.........0 0 ... x-a=[x+(n-1)a](x-a)^(n-1)x -1 0 ... 0 00 x -1 ... 0 0..............0 0 0 ... x -1an an-1 an-2 ... a2 x+a1=x -1 0 ... 0 0x^2 0 -1 ... 0 0..............x^(n-1) 0 0 ... 0 -1(x^...

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