s[1]=a[1]=(9/8)a[1]-4+m,and,a[1]>=64/3,so,a[1]=32-8m,m<=4/3s[n]=(9/8)a[n]-(4/3)*3^n+m,s[n-1]=(9/8)a[n-1]-(4/3)*3^(n-1)+ms[n]-s[n-1]=a[n]=[(9/8)a[n]-(4/3)*3^n+m]-[(9/8)a[n-1]-(4/3)*3^(n-1)+m]=(9/8)a[n]-(9/8)a[n-1]-(9/8)*3^n,so,a[n]-9a[n-1]-(64/9)*3^n=0，a[n]+(32/9)*3^n=9[a[n-1]+(32/9)*3^(n-1)]记b[n]=a[n]+(32/9)*3^n，b[1]=a...
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