方程(x-1)/(x-2)+(x-5)/(x-6)=(x-6)/(x-7)+x/(x-1)

显示全部楼层 · 2012-2-25 17:01:03

(x-1)/(x-2)+(x-5)/(x-6)=(x-6)/(x-7)+x/(x-1)所以(x-2+1)/(x-2)+(x-6+1)/(x-6)=(x-7+1)/(x-7)+（x-1+1)/(x-1)1/(x-2)+1/(x-6)=1/(x-7)+1/(x-1)1/(x-2)-1/(x-1)-=1/(x-7)-1/(x-6)然后再通分得1/(x-2)(x-1)=1/(x-7)(x-6)(x-2)(x-1)=(x-7)(x-6)展开化简得10x=40x=4由于此是分式方程还要验根2/(2x-5)-1/(x-5)=2/(2x-1)-1/(x-3)移项2/(2x-5)-2/(2x-1)=1/(x-5)-1/(x-3)然后再...

千问 · 2012-2-25 17:01:03

(x-1)/(x-2)+(x-5)/(x-6)=(x-6)/(x-7)+x/(x-1)1+1/(x-2)+1+1/(x-6)=1+1/(x-7)+1+1/(x-1)1/(x-2)-1/(x-1)=1/(x-7)-1/(x-6)1/[(x-2)(x-1)]=1/[(x-7)(x-6)](x-2)(x-1)=(x-7)(x-6)x^2-3x+...