解分式方程：(x-4)/(x-5)+(x-8)/(x-9)=(x-7)/(x-8)+(x-5)/( x-6)

显示全部楼层 · 2013-4-21 00:10:01

这道题不用那么复杂。先移项。(x-4)/(x-5)-(x-5)/(x-6)=(x-7)/(x-8)-(x-8)/( x-9)再通分。（x-4)(x-6)/(x-5)(x-6)-(x-5)(x-5)/(x-5)(x-6)=(x-7)(x-9)/(x-8)(x-9)-(x-8)(x-8)/(x-8)(x-9)再化简。(xˇ2-10x+24-xˇ2+10x-25)/(x-5)(x-6)=(xˇ2-16x+63-xˇ2+16x-64)/(x-8)(x-9)得：-1/(xˇ2-11x+30)=-1/(xˇ2-1...

千问 · 2013-4-21 00:10:01

左右两边同乘以(X-5)(X-6)(X-8)(X-9)得到(X-4)(X-6)(X-8)(X-9)-(X-5)(X-5)(X-8)(X-9)=(X-5)(X-6)(X-7)(X-9)-(X-5)(X-6)(X-8)(X-8)整理得到-(X-8)(X-9)=-(X-5)(X-6)展开解得X=7...

千问 · 2013-4-21 00:10:01

x-4)/(x-5)= 1- 1/(x-5)因此， 2-(1/(x-5) +1/(x-9)) =2+ 1/(x-8) +1/(x-6)即：0= 1/(x-8) +1/(x-6)+1/(x-5) +1/(x-9)可以看出 X 在 5-9中间这回就猜吧？其实 X-5 = 9-xX=7...