八年级下册分式解方程,求计算过程

显示全部楼层 · 2012-2-24 22:02:17

（1）1/（x-1)=1/(x+1)(x-1)
(同乘x-1)得
1=1/(x+1)
1=x+1
x=0(2)同乘(x-2)得：1+3(x-2)=x-1
1+3x-6=x-1
2x=4
x=2
(3)同乘(3+x):
2-x=1/2(x+3)+1
2-x=1/2x+3/2+1
-1/2=3/2x
x=-1/3不清楚答案对不对你可以验算...

千问 · 2012-2-24 22:02:17

（1）1/(x-1)=1/(x2-1)x2-1=x-1x(x-1)=0x=0；或x=1（增根，舍去)所以：x=0(2)1/(x-2)+3=(x-1)/(x-2)(x-2)/(x-2)=3无解(3)(2-x)/(3+x)=1/2+1/(x+3)(x-1)/(x+3)=-1/22-2x=x+...

千问 · 2012-2-24 22:02:17

（1）1/(x-1)=1/(x2-1)交叉相乘得：x2-1=x-1x(x-1)=0x=0；或x=1（增根，舍去)所以：x=0(2)1/(x-2)+3=(x-1)/(x-2)移项得：(x-2)/(x-2)=3无解(3)(2-x)/(3+x)=1/2+1/(x+3)移项得：(x-1)/(...