解方程4(x-3)(x-1)-(2x-3)^2-6=0

显示全部楼层 · 2013-4-18 00:48:32

4(x-3)(x-1)-(2x-3)^2-6=04(x^2-4x+3)-4x^2+12x-9-6=04x^2-16x+12-4x^2+12x-9-6=0-4x=9+6-12=3x=-3/4...

千问 · 2013-4-18 00:48:32

4x^2+12-16x-(4x^2+9-12x)-6=04x^2+12-16x-4x^2-9+12x-6=0-4x-3=0x=-3/4...

千问 · 2013-4-18 00:48:32

4(x-3)(x-1)-(2x-3)^2-6=04x^2-16x+12-4x^2+12x-9-6=0-4x-3=0x=-3/4...

千问 · 2013-4-18 00:48:32

解：4x2-16x＋12-﹙4x2＋9-12x﹚-6=0
4x2-16x＋12-4x2＋12x-9-6=0
4x=-3
...

千问 · 2013-4-18 00:48:32

4x2-16x＋12-﹙4x2＋9-12x﹚-6=04x2-16x＋12-4x2-9＋12x-6=04x=-3x=-3/4...