已知函数f(x)=sin(ωx-π/6)sin(ωx+π/3),相邻两条对称轴之间的距离为π/2，

显示全部楼层 · 2012-7-14 18:48:33

(wx+π/3)-(wx-π/6)=π/2==>(wx+π/3)=π/2+(wx-π/6)两边取正弦得：sin(wx+π/3)=sin[π/2+(wx-π/6)]=cos(wx-π/6)f(x)=1/2sin(2wx-π/3)因为相邻两条对称轴之间的距离为π/2即：T/2=π/2==>T=π=2π/2w==>w=1所以：f(x)=1/2sin(2x-π/3)因为f(A)=f(B)=1/4,所以：1/2sin(2A-π/3)=1/2sin(2B-π/3)=1/4sin(2A-π/3)=sin(2B-π/3)=1/22A-π/3=π/6 ;2B-π/3=5π/6 ==>A=π/4 ...

千问 · 2012-7-14 18:48:33

等于1，过程太麻烦，懒得写了...