本来下午能解答的..但是当时用JS写方法...发现有几个小时的差..一直不知道怎么解决...刚刚用C#重写了..终于知道了为什么了要说的是..你的思路是错误的..因为你忽略了闰年~~下面是C#的代码 : (.Net的DateTime对象返回的是100纳秒的时间单位,年份是从AD1开始计算的,纳秒我也不会换算成毫秒,系数是网上找到的~)
class Program
{
//定义必须变量
const int _1M = 60;
//分钟
const int _1H = _1M * 60;
//小时
const int _1D = _1H * 24;
//天
const long _1Y = _1D * 365;
//年(非闰年)
const long _YS = _1Y * 3 + _1D * 366; //一个闰年年度
const long _30D = _1D * 30;
//30天(月)
const long _31D = _1D * 31;
//31天(月)
const long _28D = _1D * 28;
//28天(月)
const long _29D = _1D * 29;
//29天(月)
long[] NormalYear = { _31D, _28D, _31D, _30D, _31D, _30D, _31D, _31D, _30D, _31D, _30D, _31D };
//年
long[] LeapYear = { _31D, _29D, _31D, _30D, _31D, _30D, _31D, _31D, _30D, _31D, _30D, _31D };
//闰年static void Main(string[] args)
{
Program P = new Program();
System.Console.WriteLine(P.getDate(P.getTimeSpame()));
DateTime T = DateTime.Now;
System.Console.WriteLine(P.getTimeSpame() + " : " + P.getTimeSpame(T.Year, T.Month, T.Day, T.Hour, T.Minute, T.Second));
System.Console.ReadKey();
}
private Program() {}
public string getDate(long TimeSp)
{
//年,月,天,小时,分钟,秒
int year = 0;
int month = 0;
int day = 0;
int hour = 0;
int minute = 0;
int second = 0;
//DateTime now = DateTime.Now;
//long TimeSp = getTimeSpame();
//当前时间戳
//年
int _y1 = (int)(TimeSp / _YS);
//获得按年度得到的年度
TimeSp -= _YS * _y1;
//计算剩余秒
int _y2 = (int)(TimeSp / _1Y);
//剩余年
TimeSp -= _1Y * _y2;
year = _y1 * 4 + _y2 + 1970;
//月
long[] YearArr = isLeapYear(year) ? LeapYear : NormalYear;//获取年的月度表
month = 1;
//从1月开始计算
for (int i = 0; i < YearArr.Length; i++)
{
if (TimeSp - YearArr < 0) break;
++month;
TimeSp -= YearArr;
}
//天
day = (int)(TimeSp / _1D);
TimeSp -= day * _1D;
//时
hour = (int)(TimeSp / _1H);
TimeSp -= hour * _1H;
//分
minute = (int)(TimeSp / _1M);
//秒
second = (int)(TimeSp % _1M);string DateStr = year + "年" + month + "月" + day + "日 " + hour + "点" + minute + "分" + second + "秒";
return DateStr;
}
//判断是否闰年
private bool isLeapYear(int year)
{
return (year % 4 == 0 ? true : false);
}
//获取当前时间戳 按1970年开始计算,精度为秒!
private long getTimeSpame()
{
DateTime _Now = DateTime.Now;
DateTime _1970 = new DateTime(1970, 1, 1);
long _Sp = (_Now.Ticks - _1970.Ticks) / 10000000;
return _Sp;
}//按既定格式把时间转成成时间戳
private long getTimeSpame(int Year, int Month, int Day, int Hour, int Minute, int Second)
{
long val = 0;
val += Second;
//秒
val += Minute * _1M;
//分钟
val += Hour * _1H;
//小时
val += Day * _1D;
//天
long[] YearArr = isLeapYear(Year) ? LeapYear : NormalYear;
for (int i = 0; i < Month - 1; i++)
{
val += YearArr;
}
Year -= 1970;
val += (Year / 4) * _YS;
Year -= (int)(Year / 4) * 4;
val += Year * _1Y;
return val;
}
}然后是JS的: (后来用C#完成后才发现,JS的Date对象的getTime()方法返回的是UTC的时间戳,这个手册上居然没明示,不过有getTimezoneOffset()方法来返回与UTC时差的分钟~)// 定义常量var _1M = 60;
//分钟var _1H = _1M * 60;
//小时var _1D = _1H * 24;
//天var _1Y = _1D * 365;
//年(非闰年)var _YS = _1Y * 3 + _1D * 366; //一个闰年年度var _30D = _1D * 30;
//30天(月)var _31D = _1D * 31;
//31天(月)var _28D = _1D * 28;
//28天(月)var _29D = _1D * 29;
//29天(月)var NormalYear = [ _31D, _28D, _31D, _30D, _31D, _30D, _31D, _31D, _30D, _31D, _30D, _31D ];
//年var LeapYear = [ _31D, _29D, _31D, _30D, _31D, _30D, _31D, _31D, _30D, _31D, _30D, _31D ];
//闰年var Now = new Date();TimeSp = Now.getTime() / 1000;//alert(Now.getTimezoneOffset());
// 时区差TimeSp += -1 * Now.getTimezoneOffset() * _1M; // 修正UTC//年,月,天,小时,分钟,秒var year = month = day = hour = minute = second = 0;//年var _y1 = parseInt(TimeSp / _YS);
//获得按年度得到的年度TimeSp -= _YS * _y1;
//计算剩余秒var _y2 = parseInt(TimeSp / _1Y);
//剩余年TimeSp -= _1Y * _y2;year = _y1 * 4 + _y2 + 1970;//月var YearArr = year % 4 == 0 ? LeapYear : NormalYear;//获取年的月度表month = 1;
//从1月开始计算for (i=0; i<YearArr.length; i++){ if (TimeSp - YearArr < 0) break; ++month; TimeSp -= YearArr;}//天day = parseInt(TimeSp / _1D);TimeSp -= day * _1D;//时hour = parseInt(TimeSp / _1H);TimeSp -= hour * _1H;//分minute = parseInt(TimeSp / _1M);//秒second = parseInt(TimeSp % _1M);var DateStr = year + "年" + month + "月" + day + "日 " + hour + "点" + minute + "分" + second + "秒";alert(DateStr);
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