f(x)=|sinx|+|cosx|①x∈[2kπ,2kπ+π/2)时f(x)=sinx+cosx=√2sin(x+π/4)x+π/4∈[2kπ+π/4,2kπ+3π/4)所以 f(x)在[2kπ,2kπ+π/4]上是单调递增的
在(2kπ+π/4,2kπ+π/2)上是单调递减的当 x=2kπ+π/2时 f(x)=1②x∈[2kπ+π/2,2kπ+π)时f(x)=sinx-cosx=√2sin(x-π/4)x-π/4∈[2kπ+π/4,2kπ+3π/4)所以 f(x)在[2kπ+π/2,2kπ+3π/4)上是单调递增的
在[2kπ+3π/4,2kπ+π)上...
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